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If lines represented by equation $\mathrm{px}^2-\mathrm{qy}^2=0$ are distinct, then
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Verified Answer
The correct answer is:
$\mathrm{p} \mathrm{q}>0$
Lines represented by $\mathrm{px}^2-\mathrm{qy}^2=0$ are distinct.
Here $\mathrm{h}=0, \mathrm{a}=\mathrm{p}$ and $\mathrm{b}=-\mathrm{q}$
Now $\mathrm{h}^2-\mathrm{ab}>0 \Rightarrow 0+\mathrm{pq}>0 \Rightarrow \mathrm{pq}>0$
Here $\mathrm{h}=0, \mathrm{a}=\mathrm{p}$ and $\mathrm{b}=-\mathrm{q}$
Now $\mathrm{h}^2-\mathrm{ab}>0 \Rightarrow 0+\mathrm{pq}>0 \Rightarrow \mathrm{pq}>0$
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