Join the Most Relevant JEE Main 2025 Test Series & get 99+ percentile! Join Now
Search any question & find its solution
Question: Answered & Verified by Expert
If log10x3-y3x3+y3=2 , then dydx=
MathematicsDifferentiationMHT CETMHT CET 2018
Options:
  • A xy
  • B -yx
  • C -xy
  • D yx
Solution:
1397 Upvotes Verified Answer
The correct answer is: yx
Given, log10x3-y3x3+y3=2
x3-y3x3+y3=102=100
Applying componendo and dividendo, we get, 
x3y3=-10199xy=-1019913......(i)
Hence, y=-9910113x
Differentiating, we get,
dydx=-9910113=yx (from (i))

Looking for more such questions to practice?

Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.