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Question: Answered & Verified by Expert

If m is the A.M. of two distinct real numbers I and n I, n>1  and G1, G2 and G3 are three geometric means between I and n, then G14+2G24+G34 equals

MathematicsSequences and SeriesJEE MainJEE Main 2015 (04 Apr)
Options:
  • A 4l2m2 n2
  • B 4 l2mn
  • C 4 lm2 n
  • D 4lmn2
Solution:
1752 Upvotes Verified Answer
The correct answer is: 4 lm2 n
Given, m is the A.M. of l & n. 

m=l+n2  ...1

G1, G2, G3 are G.M. between l & n.

l, G1, G2, G3, n are in G.P.

n=lr4  ⇒r4=nl  ...2

G1=lr, G2=lr2, G3=lr3

G14+2G24+G34=l4r4+2×l4r8+l4×r12

=l4r41+2r4+r8

=l4×nl1+r42=l3n×1+nl2

=l3×n×l+n2l2

=ln×2m2   (From (1))

=4lm2n

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