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If $M$ is the mass of the earth and $R$ its radius, the ratio of the gravitational acceleration and the gravitational constant is
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Verified Answer
The correct answer is:
$\frac{M}{R^{2}}$
The gravitational acceleration on earth is given by
$\begin{aligned}
g &=\frac{F}{m}=\frac{G M m}{R^{2} \times m}=\frac{G M}{R^{2}} \\
\therefore \quad \frac{g}{G} &=\frac{M}{R^{2}}
\end{aligned}$
$\begin{aligned}
g &=\frac{F}{m}=\frac{G M m}{R^{2} \times m}=\frac{G M}{R^{2}} \\
\therefore \quad \frac{g}{G} &=\frac{M}{R^{2}}
\end{aligned}$
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