If ' m ' is the mean of a Poisson distribution, then P x 0 =

Question

If ' m ' is the mean of a Poisson distribution, then P x > 0 =, e - m, 1 - e m, e m - 1 e m, m - e

MARKS App · Accepted Answer

If ' m ' is the mean of a Poisson distribution, then P x = k = m k . e - m k ! Now, P x > 0 = 1 - P x = 0 ⇒ P x > 0 = 1 - m x . e - m x ! = 1 - 1 e m 1 = e m - 1 e m

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