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If \( \mathrm{f} \) is a real valued function defined by \( \mathrm{f}(\mathrm{x}+\mathrm{y})+\mathrm{f}(\mathrm{x}-\mathrm{y})=\mathrm{f}(2 \mathrm{x}) \), then the value of \( \int_{\mathrm{f}(2)}^{\mathrm{f}(-2)} \mathrm{f}(\mathrm{x}) \) is equal to
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The correct answer is:
\( 0 \)
Put
is an odd function.
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