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Question: Answered & Verified by Expert
If \( \mathrm{f} \) is a real valued function defined by \( \mathrm{f}(\mathrm{x}+\mathrm{y})+\mathrm{f}(\mathrm{x}-\mathrm{y})=\mathrm{f}(2 \mathrm{x}) \), then the value of \( \int_{\mathrm{f}(2)}^{\mathrm{f}(-2)} \mathrm{f}(\mathrm{x}) \) is equal to
MathematicsDefinite IntegrationJEE Main
Options:
  • A \( 0 \)
  • B \( 1 \)
  • C \( 2 \)
  • D \( 3 \)
Solution:
1495 Upvotes Verified Answer
The correct answer is: \( 0 \)
fx+y+fx-y=f2x=fx+y+x-y
Put x=0, y=-x
fx+f-x=0fx=-fxfx is an odd function.
f2=-f-2
f2f-2fxdx=f2-f2fxdx=0

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