If $\mathrm{g}$ is the acceleration due to gravity on the surface of the earth, the gain in potential energy of an object of mass $\mathrm{m}$ raised from the earth's surface to a height equal to the radius $R$ of the earth is

Question

If $\mathrm{g}$ is the acceleration due to gravity on the surface of the earth, the gain in potential energy of an object of mass $\mathrm{m}$ raised from the earth's surface to a height equal to the radius $R$ of the earth is, $\frac{\mathrm{mg} \mathrm{R}}{4}$, $\frac{m g R}{2}$, $m g R$, $2 \mathrm{mg} \mathrm{R}$

MARKS App · Accepted Answer

Hints: $\Delta \mathrm{U}=\frac{\mathrm{mgh}}{1+\frac{\mathrm{h}}{\mathrm{R}}}=\frac{\mathrm{mgR}}{1+\frac{\mathrm{R}}{\mathrm{R}}}=\frac{\mathrm{mgR}}{2}$

Search any question & find its solution

Looking for more such questions to practice?