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If \(\mathrm{NaCl}\) is doped with \(10^{-3} \mathrm{~mol} \%\) of \(\mathrm{SrCl}_2\), what is the concentration of cation vacancies?
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The correct answer is:
\(10^{-6}\)
Correct Option is : (B)
\(10^{-6}\)
\(10^{-6}\)
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