If \( \mathrm{pK}_{\mathrm{a}} \) of a weak acid is \( 5 \), then \( \mathrm{pK}_{\mathrm{b}} \) of the conjugate base will be

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If \( \mathrm{pK}_{\mathrm{a}} \) of a weak acid is \( 5 \), then \( \mathrm{pK}_{\mathrm{b}} \) of the conjugate base will be

ChemistryIonic EquilibriumJEE Main

Solution:

1132 Upvotes Verified Answer

The correct answer is: 9

From the formula:
${pK}_{a} + {pK}_{b} = 14 \Rightarrow {pK}_{b} = 14 - {pK}_{a} = 14 - 5 = 9$
Therefore, the ${pK}_{b}$ of the conjugate base will be $9$ .

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