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Question: Answered & Verified by Expert
If \(\mathrm{p}^{\text {th }}, \mathrm{q}^{\text {th }}\) and \(\mathrm{r}^{\text {th }}\) terms of H.P. are \(\mathrm{u}, \mathrm{v}, \mathrm{w}\) respectively, then find the value of the expression \((q-r) v w+(r-p) w u+(p-q) u v\).
MathematicsSequences and SeriesBITSATBITSAT 2011
Options:
  • A 2
  • B 0
  • C 4
  • D 8
Solution:
1506 Upvotes Verified Answer
The correct answer is: 0
Let H.P. be \(\frac{1}{\mathrm{a}}+\frac{1}{\mathrm{a}+\mathrm{d}}+\frac{1}{\mathrm{a}+2 \mathrm{~d}}+\ldots \ldots\)
\(\begin{aligned}
& \therefore \mathrm{u}=\frac{1}{\mathrm{a}+(\mathrm{p}-1) \mathrm{d}}, \mathrm{v}=\frac{1}{\mathrm{a}+(\mathrm{q}-1) \mathrm{d}}, \\
& \mathrm{w}=\frac{1}{\mathrm{a}+(\mathrm{r}-1) \mathrm{d}} \Rightarrow \mathrm{a}+(\mathrm{p}-1) \mathrm{d}=\frac{1}{\mathrm{u}} \\
& \mathrm{a}+(\mathrm{q}-1) \mathrm{d}=\frac{1}{\mathrm{v}}, \mathrm{a}+(\mathrm{r}-1) \mathrm{d}=\frac{1}{\mathrm{w}} \\
& \Rightarrow(\mathrm{q}-\mathrm{r})\{\mathrm{a}+(\mathrm{p}-1) \mathrm{d}\}+(\mathrm{r}-\mathrm{p})\{\mathrm{a}+(\mathrm{q}-1) \mathrm{d}\}+\ldots \ldots \\
& =\frac{1}{\mathrm{u}}(\mathrm{q}-\mathrm{r})+\frac{1}{\mathrm{v}}(\mathrm{r}-\mathrm{p})+\ldots . \Rightarrow(q-r) \mathrm{vw}+\ldots . . = 0
\end{aligned}\)

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