Join the Most Relevant JEE Main 2025 Test Series & get 99+ percentile! Join Now
Search any question & find its solution
Question: Answered & Verified by Expert
If minimum possible work is done by a refrigerator in converting 100 grams of water at 0 °C to ice, how much heat (in calories) is released to the surroundings at temperature 27 °C (Latent heat of ice= 80 Cal/gram) to the nearest integer?
PhysicsThermodynamicsJEE MainJEE Main 2020 (03 Sep Shift 2)
Solution:
1941 Upvotes Verified Answer
The correct answer is: 8791

Q2=mL=8000

wQ2=Q1-Q2Q2=T1-T2T2

Q1-80008000=27273

Q1=8791

Looking for more such questions to practice?

Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.