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If molarity of $\mathrm{Cu}^{+2}$ ions is $3 \times 10^{-4}$ express this in ppm
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0.3
When solute is present in trace quantities, the concentration is expressed in parts per millions $(\mathrm{ppm})$ or $\mu \mathrm{gmL}^{-1}$.
100 ml of solution $=3 \times 10^{-4} \mathrm{Cu}^{2+}$ ions
$10^6 \mathrm{ml}$ of solution $=\frac{3 \times 10^{-4}}{100} \times 10^6=0.3 \mathrm{ppm}$
100 ml of solution $=3 \times 10^{-4} \mathrm{Cu}^{2+}$ ions
$10^6 \mathrm{ml}$ of solution $=\frac{3 \times 10^{-4}}{100} \times 10^6=0.3 \mathrm{ppm}$
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