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If $\mathrm{N}_0$ is the original mass of the substance of half- life period $\mathrm{t}_{1 / 2}=5$ years, then the amount of substance left after 15 years is
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The correct answer is:
$\mathrm{N}_0 / 8$
$\mathrm{N}_0 / 8$
Amount left $=N_0 / 2^n=N_0 / 8 \quad($ Here $n=15 / 5=3)$
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