If n 1 , n 2 and n 3 are the fundamental frequencies of three segments into which a string is divided, then the original fundamental frequency n of the string is given by:

Question

If n 1 , n 2 and n 3 are the fundamental frequencies of three segments into which a string is divided, then the original fundamental frequency n of the string is given by:, 1 n = 1 n 1 + 1 n 2 + 1 n 3, 1 n = 1 n 1 + 1 n 2 + 1 n 3, n = n 1 + n 2 + n 3, n = n 1 + n 2 + n 3

MARKS App · Accepted Answer

For first segment we have, n 1 = 1 2 l 1 T μ For second segment we have, n 2 = 1 2 l 2 T μ For third segment we have, n 3 = 1 2 l 3 T μ For the whole string we have, n = 1 2 l T μ Total length of the string is, l = l 1 + l 2 + l 3 Thus, the fundamental frequency for the whole string is, 1 n = 1 n 1 + 1 n 2 + 1 n 3

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