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If $n=2$ for $\mathrm{He}^{+}$ion then find out the wave length.
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$3.32 Å$
$\begin{aligned} & \text { } 2 \pi r=n \lambda \\ & 2 \pi \times 0.529 \times \frac{n^2}{Z}=n \lambda \\ & \lambda=\frac{2 \pi \times 0.529 \times n}{Z}=\frac{2 \times 3.14 \times 0.529 \times 2}{2} \\ & \lambda=3.32 Å\end{aligned}$
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