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If $n=6$, the correct sequence for filling of electrons will be
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The correct answer is:
$n s \longrightarrow(n-2) f \longrightarrow(n-1) d \longrightarrow n p$
$6 s \rightarrow 4 f \rightarrow 5 d \rightarrow 6 p$ for $n=6$
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