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If $N_{a}=\{a x \mid x \in N\}$, then what is $N_{12} \cap N_{8}$ equal to?
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Verified Answer
The correct answer is:
$N_{20}$
Given, $N_{a}=\{a x \mid x \in N$ $N_{12}=\{12,24,36,48, \ldots$
and $N_{8}=\{8,16,24, .$
$N_{12} \cap N_{8}=\{24,48, \ldots\}$
and $N_{8}=\{8,16,24, .$
$N_{12} \cap N_{8}=\{24,48, \ldots\}$
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