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Question: Answered & Verified by Expert
If Na+ ion is larger than Mg2+ ion and S2-is larger than Cl- ion, which of the following will be least soluble in water?
ChemistryChemical Bonding and Molecular StructureNEET
Options:
  • A Sodium chloride
  • B Sodium sulphide
  • C Magnesium chloride
  • D Magnesium sulphide
Solution:
1766 Upvotes Verified Answer
The correct answer is: Magnesium sulphide
Higher the lattice energy lower the solubility. Out of the four combinations possible, the lattice energy of MgS (bi-bivalent ionic solid) is higher than those of Na2S, MgCl2 (uni-bivalent or biuni-valent ionic solids ) and NaCl (univalent ionic solids) and hence, MgS is the least soluble. Thus, due to higher charge/ion, the lattice formed between Mg2+ and S2- is very strong.
As lattice energy overweighs the hydration energy here, the salt is least soluble.

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