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If $n_e$ and $n_n$ are the number of electrons and holes in a semiconductor heavily doped with phosphorus, then
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The correct answer is:
$n_e \gg n_n$
Phosphorus is a pentavalent impurity so if $n_e$ and $n_h$
are the number of electrons and holes in a semiconductor heavily doped with phosphorus, then
$n_e \gg n_h$
are the number of electrons and holes in a semiconductor heavily doped with phosphorus, then
$n_e \gg n_h$
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