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If $n$ mole of a gas changes its temperature from $T_1$ to $T_2$ at pressure $P$. If $C_P$ is given of the gas what is change in entropy?
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The correct answer is:
$n C_P \ln \left(\frac{T_2}{T_1}\right)$
$\begin{aligned} & \mathbf{} d Q=n C_P d T \\ & \frac{d Q}{T}=n C_P \frac{d T}{T} ; d S=n C_P \frac{d T}{T} \\ & \Delta S=n C_P \int_{T_1}^{T_2} \frac{d T}{T}=n C_P \ln \left(\frac{T_2}{T_1}\right)\end{aligned}$
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