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Question: Answered & Verified by Expert
If $\mathrm{Na}^{+}$ion is larger than $\mathrm{Mg}^{2+}$ ions and $\mathrm{S}^{2-}$ ion is larger than $\mathrm{Cl}^{-}$ion, which of the following will be stable salt in water?
Chemistrys Block ElementsJIPMERJIPMER 2018
Options:
  • A Sodium chloride
  • B Sodium sulphide
  • C Magnesium sulphide
  • D Magnesium chloride
Solution:
2924 Upvotes Verified Answer
The correct answer is: Magnesium sulphide
Higher the lattice energy, lower the solubility and more stable the salt in water. Since, lattice energy varies directly with charge. Therefore, among the four combinations given, the lattice energy of MgS is higher than those of $\mathrm{Na}_2 \mathrm{~S}, \mathrm{MgCl}_2$ and NaCl . Hence, MgS is stable salt in water and least soluble salt.

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