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If $\mathrm{NaCl}$ is doped with $10^{-4} \mathrm{~mol} \%$ of $\mathrm{SrCl}_2$, the concentration of cation vacancies will be: $\left(\mathrm{N}_A=6.02 \times 10^{23} \mathrm{~mol}^{-1}\right)$
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Verified Answer
The correct answer is:
$6.02 \times 10^{17} \mathrm{~mol}^{-1}$
Since each $\mathrm{Sr}^{++}$ion provides one cation vacancy, hence Concentration of cation vacancies $=$ mole $\%$ of $\mathrm{SrCl}_2$ added
$\begin{aligned}
& =10^{-4} \text { mole } \% \\
& =\frac{10^{-4}}{100} \times 6.023 \times 10^{23} \\
& =6.023 \times 10^{17} \mathrm{~mol}^{-1}
\end{aligned}$
Related Theory
Doping is the process of adding impurities to intrinsic semiconductors to alter their properties. When an intrinsic semiconductor is doped with Trivalent impurity it becomes a P-Type semiconductor. The $P$ stands for Positive, which means the semiconductor is rich in holes or Positive charged ions.
$\begin{aligned}
& =10^{-4} \text { mole } \% \\
& =\frac{10^{-4}}{100} \times 6.023 \times 10^{23} \\
& =6.023 \times 10^{17} \mathrm{~mol}^{-1}
\end{aligned}$
Related Theory
Doping is the process of adding impurities to intrinsic semiconductors to alter their properties. When an intrinsic semiconductor is doped with Trivalent impurity it becomes a P-Type semiconductor. The $P$ stands for Positive, which means the semiconductor is rich in holes or Positive charged ions.
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