If numerically greatest term in the expansion of 3 - 5 x 11 , where x = 1 5 , is 729 λ , then the value of λ 150 is

Question

If numerically greatest term in the expansion of 3 - 5 x 11 , where x = 1 5 , is 729 λ , then the value of λ 150 is,

MARKS App · Accepted Answer

3 - 5 x 11 = 3 11 1 - 5 3 x 11 Now, m = - 5 x 3 11 + 1 - 5 x 3 + 1 = 1 3 × 12 4 3 = 3 ⇒ The greatest terms in the expansion are T 3 and T 4 Greatest term T 3 = T 2 + 1 = 3 11 11 C 2 - 1 3 2 = 3 9 × 11 C 2 = 11 × 10 2 × 3 3 × 3 6 = 55 × 27 × 729 ⇒ λ = 55 × 2 7 ⇒ λ 150 = 9 . 9

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