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Question: Answered & Verified by Expert
If one of the diameters of the circle \( x^{2}+y^{2}-2 x-6 y+6=0 \) is a chord of another circle \( { }^{\prime} C^{\prime} \), whose center is at \( (2,1) \), then its radius is
MathematicsCircleJEE Main
Solution:
2490 Upvotes Verified Answer
The correct answer is: 3

x2+y2+2x-6y+6=0
center 1,3

radius =2
distance between 1,3 and 2,1 is 5

 52+22=r2

 r=3

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