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If one of the lines given by $6 x^2-x y+4 c y^2=0$ is $3 x+4 y=0$, then $c$ equals
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The correct answer is:
$-3$
$-3$
$m_1+m_2=\frac{1}{4 c}, m_1 m_2=\frac{6}{4 c}$ and $m_1=-\frac{3}{4}$ Hence c $=-3$
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