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If one of the roots of the equation $x^{2}+a x-6=0$ is 1 , then what is $(\mathrm{a}-6)$ equal to?
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Verified Answer
The correct answer is:
-1
Since 1 is the root of given equation $\therefore$ it satisfies the equation. $\therefore(1)^{2}+a(1)-6=0$
$\Rightarrow a-6=-1$
$\Rightarrow a-6=-1$
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