If $\mathrm{p}=\left[\begin{array}{lll}1 & \alpha & 3 \\ 1 & 3 & 3 \\ 2 & 4 & 4\end{array}\right]$ is the adjoint of the $3 \times 3$ matrix $\mathrm{A}$ and $\operatorname{det} \mathrm{A}=4$, then $\alpha$ is equal to