Search any question & find its solution
Question:
Answered & Verified by Expert
If $P(32,6)=k C(32,6)$, then what is the value of $k$ ?
Options:
Solution:
1061 Upvotes
Verified Answer
The correct answer is:
720
Since ${ }^{32} \mathrm{P}_{6}=\mathrm{k}^{32} \mathrm{C}_{6}$
$\Rightarrow \frac{32 !}{(32-6) !}=k \cdot \frac{32 !}{6 !(32-6) !}$
$\Rightarrow \mathrm{k}=6 !=720$
$\Rightarrow \frac{32 !}{(32-6) !}=k \cdot \frac{32 !}{6 !(32-6) !}$
$\Rightarrow \mathrm{k}=6 !=720$
Looking for more such questions to practice?
Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.