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If $P^{\prime}\left(A^{\prime}\right)+P\left(B^{\prime}\right) P(A \cup B)=0.7$ then $P^{\prime}\left(A^{\prime}\right)+P\left(B^{\prime}\right)$ is
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The correct answer is:
$1.1$
$\begin{aligned} & P\left(A^{\prime}\right)+P\left(B^{\prime}\right)=1-P(A)+1-P(B) \\ & =2-\{P(A)+P(B)\} \\ & =2-\{P(A \cup B)+P(A \cap B)\} \\ & =2-\{0.7+0.2\} \\ & =2-0.9 \\ & =1.1\end{aligned}$
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