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If $\mathrm{p} \rightarrow(\sim \mathrm{p} \vee \mathrm{q})$ is false, then the truth values of $\mathrm{p}$ and $\mathrm{q}$ are respectively
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T, F
(D)
We know that $\mathrm{T} \rightarrow \mathrm{F}$ is false.
$\therefore \mathrm{p}$ must be true and $(\sim \mathrm{p} \vee \mathrm{q})$ must be false. $\Rightarrow \mathrm{p}$ is true.
We know that $\mathrm{F} \vee \mathrm{F}$ is false.
So $\mathrm{q}$ must be false.
We know that $\mathrm{T} \rightarrow \mathrm{F}$ is false.
$\therefore \mathrm{p}$ must be true and $(\sim \mathrm{p} \vee \mathrm{q})$ must be false. $\Rightarrow \mathrm{p}$ is true.
We know that $\mathrm{F} \vee \mathrm{F}$ is false.
So $\mathrm{q}$ must be false.
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