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If $p \rightarrow(p \wedge \sim q)$ is false, then the truth values of $p$ and $q$ are respectively
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Verified Answer
The correct answer is:
$\mathrm{T}, \mathrm{T}$
$\mathrm{p} \rightarrow(\mathrm{p} \wedge \sim \mathrm{q})$ will be false if
$\mathrm{P}$ is true and $\mathrm{p} \wedge \sim \mathrm{q}$ is false
$\Rightarrow \mathrm{P}$ is true and $\mathrm{q}$ is true
$\mathrm{P}$ is true and $\mathrm{p} \wedge \sim \mathrm{q}$ is false
$\Rightarrow \mathrm{P}$ is true and $\mathrm{q}$ is true
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