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If $p, q, r$ are simple propositions, then $(p \wedge q) \wedge(q \wedge r)$ is true then
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$p, q, r$ are all true
$(p \wedge q) \wedge(q \wedge r)$ is true means $p \wedge q, q \wedge r$ are both true. $\Rightarrow p, q, r$ are all true.
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