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If $p, q, r$ are simple propositions with truth alues $\mathrm{T}, \mathrm{F}, \mathrm{T}$, then the truth value of $(\sim p \vee q) \wedge \sim r \Rightarrow p$ is
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The correct answer is:
True
$\sim p \vee q$ means $F \vee F=F, \sim r$ means $F$
$(\sim p \vee q) \wedge \sim r$ means $F$
$[(\sim p \vee q) \wedge \sim r] \Rightarrow p$ means $\mathrm{T}$
$(\sim p \vee q) \wedge \sim r$ means $F$
$[(\sim p \vee q) \wedge \sim r] \Rightarrow p$ means $\mathrm{T}$
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