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If $p, q, r$ are simple propositions with truth values $\mathrm{T}, \mathrm{F}, \mathrm{T}$, then the truth value of $(\sim p \vee \mathrm{q}) \wedge \sim r$ $\Rightarrow p$ is
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true
$\sim \mathrm{p} \vee \mathrm{q}$ means $\mathrm{F} \vee \mathrm{F}=\mathrm{F}, \sim \mathrm{r}$ means $\mathrm{F}$
$\therefore \quad[(\sim \mathrm{p} \vee \mathrm{q}) \wedge \sim \mathrm{r}] \Rightarrow \mathrm{p}$ means $\mathrm{T}$
$\therefore \quad[(\sim \mathrm{p} \vee \mathrm{q}) \wedge \sim \mathrm{r}] \Rightarrow \mathrm{p}$ means $\mathrm{T}$
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