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If $P(x)=a x^2+b x+c$ and $Q(x)=-a x^2+d x+c$ where $a c \neq 0$, then $P(x) \cdot Q(x)=0$ has at least
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Two real roots
Let all four roots are imaginary. Then roots of both equations $P(x)=0$ and $Q(x)=0$ are imaginary. Thus $b^2-4 a c \lt 0 ; d^2+4 a c \lt 0$, So $b^2+d^2 \lt 0$ which is impossible unless $b=0, d=0$
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