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Question: Answered & Verified by Expert
If $P(x)=a x^2+b x+c$ and $Q(x)=-a x^2+d x+c$ where $a c \neq 0$, then $P(x) \cdot Q(x)=0$ has at least
MathematicsQuadratic EquationJEE Main
Options:
  • A Four real roots
  • B Two real roots
  • C Four imaginary roots
  • D None of these
Solution:
1721 Upvotes Verified Answer
The correct answer is: Two real roots
Let all four roots are imaginary. Then roots of both equations $P(x)=0$ and $Q(x)=0$ are imaginary. Thus $b^2-4 a c \lt 0 ; d^2+4 a c \lt 0$, So $b^2+d^2 \lt 0$ which is impossible unless $b=0, d=0$

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