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If \( P(A \cap B)=\frac{7}{10} \) and \( P(B)=\frac{17}{20} \), where \( P \) stands for probability then \( P(A \mid B) \) is equal to
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The correct answer is:
\( \frac{14}{17} \)
Given that, \( P(A \cap B)=\frac{7}{10} \) and \( P(B)=\frac{17}{20} \)
We know that, \( P(A \mid B)=\frac{P(A \cap B)}{P(B)} \)
\( P(A \mid B)=\frac{\frac{7}{10}}{\frac{17}{20}}=\frac{14}{17} \)
We know that, \( P(A \mid B)=\frac{P(A \cap B)}{P(B)} \)
\( P(A \mid B)=\frac{\frac{7}{10}}{\frac{17}{20}}=\frac{14}{17} \)
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