Join the Most Relevant JEE Main 2025 Test Series & get 99+ percentile! Join Now
Search any question & find its solution
Question: Answered & Verified by Expert
If pH of a saturated solution of BaOH2 is 12, the value of its K(sp) is found to be n×10-7M3. find the value of n here?
ChemistryIonic EquilibriumJEE Main
Solution:
1710 Upvotes Verified Answer
The correct answer is: 5
As pH=12
pOH=14-12=2
[OH]=10-2M=0.01M/L
In case of Ba(OH)2sBa+2s+2OH-22s
As 2s=0.01m/L
s=0.012=5×10-3m/L
Ksp for BaOH2=4s3=45×10-33=5×10-7M3
Hence n = 5

Looking for more such questions to practice?

Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.