If pressure and temperature of an ideal gas are doubled and volume is halved, the number of molecules of gas

Question

If pressure and temperature of an ideal gas are doubled and volume is halved, the number of molecules of gas, Become half, Become two times, Become four times, Remain constant

MARKS App · Accepted Answer

Applying ideal gas equation, we have p V = n R T Where, p = pressure of the gas V = volume of the gas n = number of moles R = gas constant T = temperature of the gas ∴ n 1 = p 1 V 1 R T 1 and n 2 = p 2 V 2 R T 2 ⇒ n 2 n 1 = p 2 V 2 p 1 V 1 × T 1 T 2 = p 2 p 1 V 2 V 1 T 1 T 2 n 2 n 1 = 2 1 2 2 n 2 = 2 n 1

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