If Q ( 0 , - 1 , - 3 ) is the image of the point P in the plane 3 x - y + 4 z = 2 and R is the point ( 3 , - 1 , - 2 ) , then the area (in sq. units) of Δ P Q R is

Question

If Q ( 0 , - 1 , - 3 ) is the image of the point P in the plane 3 x - y + 4 z = 2 and R is the point ( 3 , - 1 , - 2 ) , then the area (in sq. units) of Δ P Q R is, 91 4, 91 2, 2 13, 65 2

MARKS App · Accepted Answer

Given, equation of plane is 3 x - y + 4 z - 2 = 0 . Distance, P M = 1 - 12 - 2 9 + 1 + 16 = 13 2 P R = 9 + 1 = 10 ∴ R M = 10 - 13 2 = 7 2 ∴ Area of ∆ P Q R = 2 1 2 × P M × R M = 2 1 2 × 13 2 × 7 2 = 91 2

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