Search any question & find its solution
Question:
Answered & Verified by Expert
If ' $q$ ' is electric charge, B is magnetic field, ' $R$ ' is the dee radius and ' $\mathrm{m}$ ' is the mass of ions, the kinetic energy of the ions in cyclotron is given by
Options:
Solution:
1820 Upvotes
Verified Answer
The correct answer is:
$\frac{\mathrm{q}^2 \mathrm{~B}^2 \mathrm{R}^2}{2 \mathrm{~m}}$
$\mathrm{R}=\frac{\mathrm{mv}}{\mathrm{qB}} ; \mathrm{P}=\mathrm{RqB}$
The kinetic energy of ions in cyclotron is given by
$K . E=\frac{P^2}{2 m}=\frac{q^2 R^2 B^2}{2 m}$
The kinetic energy of ions in cyclotron is given by
$K . E=\frac{P^2}{2 m}=\frac{q^2 R^2 B^2}{2 m}$
Looking for more such questions to practice?
Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.