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If S $=\left(\mathrm{x}: \mathrm{x}^{2}+\mathrm{l}=0, \mathrm{x}\right.$ is real $)$, then $\mathrm{S}$ is
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an empty set
$\mathrm{S}=\left\{\mathrm{x}: \mathrm{x}^{2}+1=0, \mathrm{x}: 5\right.$ real\}
$\mathrm{x}^{2}+1=0 \Rightarrow \mathrm{x}^{2}=-1 \Rightarrow \mathrm{x}=\sqrt{-1} \rightarrow$ complex number
No real numbers. So, $\mathrm{S}$ is empty set
$\mathrm{x}^{2}+1=0 \Rightarrow \mathrm{x}^{2}=-1 \Rightarrow \mathrm{x}=\sqrt{-1} \rightarrow$ complex number
No real numbers. So, $\mathrm{S}$ is empty set
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