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If seven women and seven men are to be seated around a circular table such that there is a man on either side of every woman, then the number of seating arrangements is
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$6 ! 7 !$
$6 ! 7 !$
7 women can be arranged around a circular table in 6 ! ways.
Among these 7 men can sit in 7 ! ways. Hence, number of seating arrangement $=7 ! \times 6 !$
Among these 7 men can sit in 7 ! ways. Hence, number of seating arrangement $=7 ! \times 6 !$
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