Join the Most Relevant JEE Main 2025 Test Series & get 99+ percentile! Join Now
Search any question & find its solution
Question: Answered & Verified by Expert
If sin3θ-cos3θsinθ-cosθ-cosθ1+cot2θ-2tanθcotθ=-1 θ0,2π, then
MathematicsTrigonometric EquationsJEE Main
Options:
  • A θ0,π2-π4
  • B θπ2,π-3π4
  • C θπ,3π2-5π4
  • D θ0,π-π4,π2
Solution:
1379 Upvotes Verified Answer
The correct answer is: θ0,π-π4,π2

Since, sinθ-cosθ0tanθ1

To define cotθ, θ0,π,2π and

to define tanθ,θπ2,3π2
θπ4,5π4,π2,3π2,0,π,2π
Now, sin2θ+cos2θ+sinθcosθ-sinθcosθ-2=-1
1+sinθcosθ-sinθcosθ=1
cosθsinθ-sinθ=0
cosθ=0 or sinθ=sinθ
θ=π2,3π2 or θ=0,π
θ0,π-π4,π2

Looking for more such questions to practice?

Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.