If sin 6 ⁡ θ + cos 6 ⁡ θ + k cos 2 ⁡ 2 θ = 1, then k is equal to

Question

If sin 6 ⁡ θ + cos 6 ⁡ θ + k cos 2 ⁡ 2 θ = 1, then k is equal to, 1 2 tan 2 ⁡ 2 θ, 1 4 tan 2 ⁡ 2 θ, 4 cot 2 ⁡ 2 θ, 3 4 tan 2 ⁡ 2 θ

MARKS App · Accepted Answer

sin 2 ⁡ θ + cos 2 ⁡ θ sin 4 ⁡ θ - sin 2 ⁡ θ cos 2 ⁡ θ + cos 4 ⁡ θ + k cos 2 ⁡ 2 θ = 1 or sin 2 ⁡ θ + cos 2 ⁡ θ 2 - 3 sin 2 ⁡ θ cos 2 ⁡ θ + k cos 2 ⁡ 2 θ = 1 or 1 - 3 sin 2 ⁡ θ cos 2 ⁡ θ + k cos 2 ⁡ 2 θ = 1 or k cos 2 ⁡ 2 θ = 3 sin 2 ⁡ θ cos 2 ⁡ θ or k cos 2 ⁡ 2 θ = 3 4 2 sin ⁡ θ cos ⁡ θ 2 or k cos 2 ⁡ 2 θ = 3 4 sin 2 ⁡ 2 θ or k = 3 4 tan 2 ⁡ 2 θ

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