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Question:
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If $\sin \alpha+\sin \beta=0=\cos \alpha+\cos \beta$, where $0 < \beta < \alpha < 2 \pi$, then
which one of the following is correct?
Options:
which one of the following is correct?
Solution:
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Verified Answer
The correct answer is:
$\alpha=\pi+\beta$
$\sin \alpha+\sin \beta=0=\cos \alpha+\cos \beta$
$\sin \alpha+\sin \beta=0$
$\Rightarrow \sin \alpha=-\sin \beta$
$\Rightarrow \sin \alpha=\sin (\pi+\beta)$
$\Rightarrow \alpha=\pi+\beta$
$\sin \alpha+\sin \beta=0$
$\Rightarrow \sin \alpha=-\sin \beta$
$\Rightarrow \sin \alpha=\sin (\pi+\beta)$
$\Rightarrow \alpha=\pi+\beta$
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