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If $\sin x=\frac{-24}{25}$, then the value of $\tan x$ is
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The correct answer is:
$\frac{-24}{7}$
$\cos x=\sqrt{1-\sin ^2 x}=\sqrt{1-\left(\frac{-24}{25}\right)^2}=\frac{7}{25}$
$\Rightarrow \tan x=\frac{\sin x}{\cos x}=\frac{-24}{7}$
$\Rightarrow \tan x=\frac{\sin x}{\cos x}=\frac{-24}{7}$
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