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If $\sin x=-\frac{3}{5}$, where $\pi < x < \frac{3 \pi}{2}$, then $80\left(\tan ^2 x-\cos x\right)$ is equal to
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109
$\begin{aligned} & \sin x=\frac{-3}{5}, \pi < x < \frac{3 \pi}{2} \\ & \tan x=\frac{3}{4} \cos x=-\frac{4}{5} \\ & 80\left(\tan ^2 x-\cos x\right) \\ & =80\left(\frac{9}{16}+\frac{4}{5}\right)=45+64=109\end{aligned}$
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