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If speed of sound in air in $330 \mathrm{~m} \mathrm{~s}^{-1}$, then find the number of overtones present in an open organ pipe of length $1 \mathrm{~m}$ whose frequency $f \leq 1000$
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$6$
Fundamental frequency,
$\begin{aligned} & v=\frac{v}{2 \ell}=\frac{330}{2 \times 1}=165 \mathrm{~Hz} \\ & \therefore \text { Number of overtones allowed }=\frac{1000}{165}=6\end{aligned}$
$\begin{aligned} & v=\frac{v}{2 \ell}=\frac{330}{2 \times 1}=165 \mathrm{~Hz} \\ & \therefore \text { Number of overtones allowed }=\frac{1000}{165}=6\end{aligned}$
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