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Question: Answered & Verified by Expert
If speed V, force F and acceleration a are chosen as the fundamental physical quantities, then the dimension of Young's modulus in terms of VF and a are
PhysicsUnits and DimensionsJEE Main
Options:
  • A V-3Fa
  • B V-4F2a2
  • C V-4Fa2
  • D V-4F2a
Solution:
2407 Upvotes Verified Answer
The correct answer is: V-4Fa2
Let Y=fV, F, a

Y=KVxFyaz,      KUnitless

Y=VxFyaz

ML-1T-2=LT-1xMLT-2yLT-2z

ML-1=T-2= MyLx+y+zT-x-2y-2z 

y=1;    x+y+z=-1;    -x-2y-2z=2

x+z=-2           x+2y+2z=2

x+2z=0              z=2, x=-4

Y=V-4Fa2

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