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If $t_{1 / 2} v \frac{1}{a^2}$ is a straight line graph then determine the order of reaction.
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Verified Answer
The correct answer is:
Third order
For a $n^{\text {th }}$ order reaction,
$t_{1 / 2} \propto \frac{1}{[a]^{n-1}}$
$t_{1 / 2} \propto \frac{1}{[a]^{3-1}} \quad[\therefore n=3]$
$t_{1 / 2} \propto \frac{1}{[a]^2}$
$t_{1 / 2} \propto \frac{1}{[a]^{n-1}}$
$t_{1 / 2} \propto \frac{1}{[a]^{3-1}} \quad[\therefore n=3]$
$t_{1 / 2} \propto \frac{1}{[a]^2}$
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